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Signal Noise Ratio Calculator
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A SNR of 2.5 dB means there might be reduction in data speed. In digital communication SNR of 16.48 dB means the data speed is clearly readable. But in wireless communication SNR of 25 dB to 40 dB is considered to be good.
For wireless network connectivity below are sample application of SNR
| If the calculated SNR is 5 dB to 10 dB: what does it mean? it means below the minimum level to establish a connection, due to the noise level being nearly indistinguishable from the desired signal (useful information). |
| If the calculated SNR is 15 dB to 25 dB: what does it mean? It means the desired signal is typically considered the minimally acceptable level to establish poor connectivity. |
| If the calculated SNR is 25 dB to 40 dB: what does it mean? it means the desired signal is deemed to be good. |
| if the calculated SNR IS 41 dB or higher: what does it mean? it means the desired signal is considered to be excellent.. Example the output desired signal is measured at 300 millivolt and the input noise signal is 2 microvolt. Calculated SNR is 103.52 dB which means the useful information signal is excellent. |
| source of information: Cadence blog |
| source of information: Wikipedia |
| source of information: Analog Devices Tutorial |
| related: Power Gain Calculator |
Communication engineer always try to design their system to get maximum SNR. Why is the multiplying constant 20 not 10 in some SNR equation. The reason why it is 20 is because SNR is usually calculated at power level. The relationship of power to voltage is P = V2/R. Hence when logarithm is evaluated = 2 * 10 log ( V signal / V noise). simplifying 2 * 10 = 20. Always remember that the signal unit of measurement and noise unit of measurement must be the same. For example given output signal is 300 millivolt and the input noise is 2 microvolt. Here the units are not the same, you must do conversion to make them the same unit of measurement. 2 microvolt = 0.000002 V. To convert microvolt to millivolt, just move the decimal point 3 position to the right and you will get 0.002 mV. Now you can use the formula below to calculate the SNR. Answer (103.52 dB)
Solve the Signal to Noise given input noise signal of 0.3 microVolt and output desired signal of 2 microVolt.
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Ar, in dB
|
= | 20 *Log 10 |
Ao Output (Signal)
Ai Input (Noise)
|
Solve for the output signal, Given the SNR is 16.48 dB and the given input signal of 0.3 microVolt.
|
Ar, in dB, Given
|
= | 20 *Log 10 |
Ao Output
Ai Input
|
Signal output, Ao = microVolt
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