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Motor Belt Speed
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Motor belt speed in feet per minute

motor image credit: Wikipedia.com

Solve for the required belt speed in FPM using specified motor 10 rpm and diameter of belt pulley is 2 inches.

Belt speed (FPM)
=
0.262 x RPM x Diameter ( inch)

Solve for the required belt pulley diameter to meet the specified belt speed of 5.24 FPM and motor 10 rpm.

Belt speed (FPM)
=
= 0.262 x RPM x Diameter
( inch)

Solve for the required motor rpm to meet the specified belt pulley diameter of 2 inches and belt speed of 5.24 FPM.

Belt speed (FPM)
=
= 0.262 x RPM x Diameter ( inch)

Memory recall lesson learned :

RPM = revolution per minute ; 1 hp = 33,000 lb-ft per minute ; 1 revolution = 2π
2π = 6.2832 ; 33,000 /6.2832 = 5252 ; 33,000 lb-ft per minute = 396,000 lb-in per min ; 396,000/6.2832 = 63024 ; FPM = feet per min ; FPM = 0.262 RPM * Diameter in inches




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