You are expected to learn how to :
Compute the current I expected flowing in any RLC circuit.
Then compute the current I1 and I2
Then compute the expected total power consumption and then compute the power consumption of impedance load 1 Z1 and the power consumption of impedance load 2 Z2



YT = 1 / ZT Explain why 1 / 4.472 ZT is not equal to Z=11.18 as shown by graphical complex number addition? Answer: The two impedances are not in series, so the complex number addition will not work because in parallel you compute the total impedance using the formula 1/Z1 + 1/Z2. To make the calculation easy admittance concept was introduced.
FORMULA RECALL : Y is the Admittance and Z is the Impedance.
Important to remember inductive load is represented by + J (positive reactance) and capacitive load - J (negative reactance) . This knowledge is very important because of the complex number conjugate when you are doing complex number division. This calculator embedded that reactance rule + j L (use positive for inductive load) and - J C (use negative for capacitive load) that affects the complex number conjugate. So be careful not to put negative sign in capacitive input box shown below. It's already accounted for.
Y 1 = 1 / Z1 =
+ J
Converting complex number to polar format
Y 1 =
°
Show me the calculation to get
0.1600 - j 0.1200
Explanation below.
Memory recall knowledge of complex number division using conjugate.

Now the calculation is automated.
Y 2 = 1 / Z2 =
+ J
Y 2 =
°
YT = Y 1 + Y 2 Total Admittance ,
YT = 1 / ZT
Addition of complex number
Y 1 + Y 2 =
+ J
Converting complex number to polar format
Y 1 + Y 2 =
°
I = I 1 + I 2 = E * Y = Total Current
*
°
Total Current, I
I =
°
I 1 = E * Y 1
*
Load 1 Current, I1
I 1 =
I 2 = E * Y 2
*
Load 2 Current, I2
I 2 =
I 1 =
+ J
I 2 =
+ J
Total current, adding complex number
I =
+ J
Total current converted to polar format
I =
Compute the total power consumption of the loads.
P = E * I * Cos (-10.3049) =
*
*
=
Watts
Compute the load 1 power consumption.
P 1 = E * I1 * Cos (-36.87) =
*
*
=
Watts
Compute the load 2 power consumption.
P 2 = E * I2 * Cos (53.1303) =
*
*
=
Watts
INITIAL DATA
R4 = 4 Ω
XL = 3
R6 = 6 Ω
XC = 8
V = 100
No need to add the negative sign for capacitive reactance because it is already embedded in the logical computation.
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