Bridge Circuit Calculator



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Calculator to solve for value of I1 = ? and value of I2 = ? and E = ?


Itotal =
Voltage drop at E_R3 = volts (70 x 0.05)
I1 = Amp
I2 = Amp
Voltage drop at E_R5 = volts (150 x 0.06)
Voltage source, E = (E_R3 + E_R5)

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Can you use this analysis in Alternating Current circuit (AC) ? Yes, because most of the metering value are reported in RMS (root mean squared) , which is the equivalent Direct Current (DC) effective value. Caution makes sure you have a very good understanding of RMS value and the metering values that you are using is actually RMS value. To quickly check if the value is RMS, there should be no negative value. Why ? because in RMS , the negative value is squared. Memory recall what we learned from multiplication of two negative numbers, the result is always positive. So if you see negative value. You can be sure that the value is not RMS value, it is waveform value.


Calculator to solve for value of I1 = ? and value of I2 = ? and Es = ?

I1 + I2 = Equation 1 for loop 1 KVL (Kirchoff Voltage Law (KVL) means add all voltages in loop 1 it must be equal to zero)

I1 + I2 = Equation 2 for loop 2 KVL (Kirchoff Voltage Law (KVL) means add all voltages in loop 2 it must be equal to zero)

INPUT DATA

I-total = 0.10 A R1 = 50 Ω R3 = 70 Ω

R2 = 100 Ω R4 = 250 Ω R5 = 150 Ω

ANSWER

Voltage drop at E_R3 = 3.5 volts
Voltage drop at E_R5 = 9 volts

Voltage source, E = volts
Voltage loop 3 is use to compute the total voltage source needed.
E_R3 + E_R5 - E = 0 KVL at loop 3.

Answer, I1 = 0.05

Answer, I2 = 0.01

When R 1 and R 4 are equal in resistance and R 3 and R 5 are also equal in resistance value,
I2 = 0 (at least very close to zero)

Compute the Itotal current when the voltage source used is 15 V.


PROBLEM #2 Can be solved by trial and error or Heuristic Method.

Using the above simulator. Try raising the Current Itotal until you reach close enough to the given voltage of 15 V.

Answer = 0.12 Amp is the total current.

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