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Maximum Short Circuit Current

Compute Maximum Short Circuit Current

Assume this transformer is a 3 phase pad mounted distribution transformer

Full Load Ampere

=

3 Phase kVA V * 1.732

COMPUTE THE MAXIMUM AVAILABLE SHORT CIRCUIT CURRENT AT 480 V BUS USING IEEE ANSI METHOD

if the bus impedance is not given , you can assume initial value based on empirical data coming from your protection relay when there is a bus fault.

For example, if you know that your transformer has % Z of 4 % and your breaker interrupted a bus fault with magnitude of 18,505 A. By trial and error approximate your bus impedance value start at value 0.0100 ohms then raise it until it is 0.025 ohms , Ω that will give you close to relay fault data.

What is the infinite bus method of estimating the short circuit current? This is my personal understanding base on my mathematical knowledge, if you divide per unit voltage by zero impedance Z you will get almost infinite current ( I = V/Z = 1/0 = infinity fault current or maximum fault current ). So, to get the maximum fault current , you need to set the value of impedance Z to be almost 0 like 0.00000099 ohms. The only impedance to limit the fault current is the transformer impedance. All other impedance are neglected or assigned a value of almost zero. Another explanation of infinite bus is constant voltage and frequency. In order to achieve constant voltage there should be zero voltage drop. Vdrop = I * Z = 0 will only happen if the impedance Z is set to almost zero like 0.00000009.

But in reality the bus bar impedance value is not zero. It could be 0.005 ohms.

Another example of Transformer short circuit calculation

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